Magnetic Potential Due to Bar Magnet

At a point on the right bisector of a magnetic dipole the magnetic-

Let the magnetic field on earth be modelled by that of a point magnetic dipole at the centre of earth. The angle of dipole a point on the geographical equator.

The magnetic field due to a dipole of pole strength $3.6\times {10}^{-3}\mathrm{A}-\mathrm{m}$ and magnetic length is $2\times {10}^{-2}\mathrm{m}$ at a point away from the mid-point of dipole is $2\mathrm{m}$ at an angle ${30}^{\mathrm{o}}$ from it is

Magnetic moment of a bar magnet is $\mathrm{M}$. The work done in turning the magnet by ${90}^{\mathrm{o}}$ in direction of magnetic field $\mathrm{B}$ will be

Find the magnetic field due to a dipole of magnetic moment $1.2{\mathrm{Am}}^2$ at a point $1\mathrm{m}$ away from it in a direction making an angle of ${60}^{\mathrm{o}}$ with the dipole axis.

Two similar bar magnets $\mathrm{P}$ and $\mathrm{Q}$ each of magnetic moment $\mathrm{M}$ are taken. If $\mathrm{P}$ is cut along its axial line and $\mathrm{Q}$ along its equatorial line all the four pieces obtained have each of-

A bar magnet has a magnetic moment of $0.4 {\mathrm{Am}}^2$. On cutting it into equal halves along equatorial line, each half will have a magnetic moment of:

A long magnet of magnetic moment $\mathrm{M}$ and a pole strength $\mathrm{m}$ is broken into two halves of equal length along the equatorial line. The magnetic moment of each half is

The magnetic field strength at a point at a distance $\mathrm{d}$ from the centre on the axial line of a very short bar magnet of magnetic moment $\mathrm{M}$ is $\mathrm{B}$. The magnetic induction at a distance $2\mathrm{d}$ from the centre on the equator line of a magnetic moment $8\mathrm{M}$ will be 

The magnetic induction field strength due to a short bar magnet at a distance $0.20\mathrm{m}$ on the equatorial line is $20\times {10}^{-6}\mathrm{T}$. The magnetic moment of the bar magnet is

The magnetic potential at a point on the axial line of a bar magnet of dipole moment $\mathrm{M}$ is $\mathrm{V}.$ What is the magnetic potential due to a bar magnet of dipole moment $\frac{\mathrm{M}}{4}$ at the same point 

A bar magnet of magnetic moment $\mathrm{M}$ is cut into two equal parts along its axis. This magnetic moment of each part is-

The magnetic induction field strength at a distance $0.2\mathrm{m}$ on the axial line of a short bar magnet of moment $3.6 {\mathrm{Am}}^2$ is

The dipole moment of the short bar magnet is $12.5 \mathrm{A}-{\mathrm{m}}^2$. The magnetic field on its axis at a distance of $0.5\mathrm{m}$ from the centre of the magnet is 

The magnetic potential a point on the axial line of a bar magnet of dipole moment $\mathrm{M}$ is $\mathrm{V}$. What is the magnetic potential due to a bar magnetc of dipole moment $\raisebox{1ex}{$\mathrm{M}$}\!\left/ \!\raisebox{-1ex}{$4$}\right.$ at the same point?

The magnetic potential due to the bar magnet in the broad-on-position is zero.

Calculate the magnetic potential at a point $2\mathrm{cm}$ on the axial line of a bar magnet of dipole moment $25 {\mathrm{Am}}^2$. 

The magnetic potential at a point on the axial line of a bar magnet of dipole moment $M$ is $V$. What is the magnetic potential due to a bar magnet of dipole moment $\frac{M}{2}$ at the same point.

Cotyledons are also called-